4x^2+32=2x^2

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Solution for 4x^2+32=2x^2 equation: 



4x^2+32=2x^2

We move all terms to the left:

4x^2+32-(2x^2)=0

We add all the numbers together, and all the variables

2x^2+32=0

a = 2; b = 0; c = +32;
Δ = b2-4ac
Δ = 02-4·2·32
Δ = -256
Delta is less than zero, so there is no solution for the equation

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